5x2-8x+5-3x2+6x
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/31 02:36:00
5x2-8x+5-3x2+6x5x2-8x+5-3x2+6x5x2-8x+5-3x2+6x5x2-8x+5-3x2+6x=﹙5-3﹚x²+﹙-8+6﹚x+5=2x²-2x+5
5x2-8x+5-3x2+6x
5x2-8x+5-3x2+6x
5x2-8x+5-3x2+6x
5x2-8x+5-3x2+6x
=﹙5-3﹚x²+﹙-8+6﹚x+5
=2x²-2x+5
5x2-8x+5-3x2+6x
5(x2-x)=3(x2+x)
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
用换元法解方程x2-3x+5+6/(x2-3x)
x2-5x+8
(x2+5x+5)/(x2+5x+6)-(x2+8x+14)/(x2+8x+15)化简
x2-5x+6
x2-5x+6
3x2+5x
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708
不等式(x2-4x-5)(x2-8)
x2-1/x2-5x+6
x2-4x+3分之x2-5x+6+s2-2x+1分之x2-4x+3+1-x2分之x2-3x-4的过程
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21x2是x的平方
(x2+5x+6)*(x2+7x+6)-3x2 (因式分解)
解分式方程:2/x2+5x+6 + 3/x2+x-6=4/x2-4
因式分解(x2+5x+6)(x2+7x+6)-3x2
x2-8x+15=0 求两根 x2-5x+6=0 求两根 注:x2是x2方啊