lim(x->∞)[x^7(1-2x)^8/(3x+2)^15]求极限答案是lim(x->∞)[x^7(1-2x)^8/(3x+2)^15]=lim(x->∞)[(1/x-2)^8/(3+2/x)^15]=(0-2)^8/(3+0)^15=2^8/3^15；x^7是怎么去掉的?还是答案错了

Lim [x^2/(x^2-1)]^x (x→∞) lim(1+x/x)2x (x→∞) 用罗必达法则解 （见图）lim [(e^x)-1/sin（5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->∞ lim 7cos(3x)sec(9x)x->pi/2 1.lim x->∞ （2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 （e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim(1-x)^(2/x) x->0 lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4 x/2-1lim(1-2/x)x→∞ lim(x→∞)(1-2/x) (x+1)次方 计算 x－∞lim(1+1/x)^2x lim(x→∞)[1+(1/x)]^x/2 lim(x→∞)(1-2/x)^2x lim x→∞(2x+1)/(3x-4) lim(x->+∞)x sin2x/x^2+1 lim x→∞ x-1/x^2 lim x→∞(1-2/x)^x= 求lim(√x^2+1)-x x→-∞ lim(x→∞)[(2x-1)^3 * (3x^2+2)^2]/x^7 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限