求lim(√x^2+1)-x x→-∞
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求lim(√x^2+1)-xx→-∞求lim(√x^2+1)-xx→-∞求lim(√x^2+1)-xx→-∞如果是负无穷lim(√x^2+1)是正的xx是负的结果为无穷大如果x趋于正无穷原式=lim(
求lim(√x^2+1)-x x→-∞
求lim(√x^2+1)-x x→-∞
求lim(√x^2+1)-x x→-∞
如果是负无穷
lim(√x^2+1)是正的
x x是负的
结果为无穷大
如果x趋于正无穷
原式=lim(x->∞) [根号下(x²+1) -x]*[根号下(x²+1) ) +x]/[根号下(x²+1) ) +x]
=lim(x->∞) [(x²+1) -x²]/[根号下(x²+1) ) +x]
=lim(x->∞) 1/[根号下(x²+1) ) +x]
=0
漏了分母的x
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