2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?
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2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?2
2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?
2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?
2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)=?
2/(x-1)-2/(x+1)-1/(x-2)+1/(x+2)
=(2x+2-2x+2)/(x+1)(x-1)-(x+2-x+2)/(x+2)(x-2)
=4/(x+1)(x-1)-4/(x+2)(x-2)
=4(x²-4-x²+1)/(x+1)(x-1)(x+2)(x-2)
=-12/(x+1)(x-1)(x+2)(x-2)
或=-12/(x²-1)(x²-4)
=-12/(x^4-5x²+4)
答:
通分即可
原式
=2[x+1-(x-1)]/(x²-1)-[x+2-(x-2)]/(x²-4)
=4/(x²-1)-4/(x²-4)
=4[x²-4-(x²-1)]/[(x²-4)(x²-1)]
=-12/(x^4-5x²+4)
=2(x+1)-2(x-1))/(x+1)(x-1)+(-2(x+2)+2(x-2))/(x+2)(x-2)
=4(x2-4)-6(x2-1))/(x2-1)(x2-4)
=(-2(x2+5))/(x2-1)(x2-4)
-12/[(x-1)(x+1)(x-2)(x+2)]
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