{3x-2y=8,2y+3z=1,x+5y-z=-4.用代入法解这个方程组
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{3x-2y=8,2y+3z=1,x+5y-z=-4.用代入法解这个方程组{3x-2y=8,2y+3z=1,x+5y-z=-4.用代入法解这个方程组{3x-2y=8,2y+3z=1,x+5y-z=-4
{3x-2y=8,2y+3z=1,x+5y-z=-4.用代入法解这个方程组
{3x-2y=8,2y+3z=1,x+5y-z=-4.用代入法解这个方程组
{3x-2y=8,2y+3z=1,x+5y-z=-4.用代入法解这个方程组
由③得,
x=-4-5y+z ④
把④带入中,得
-17y+3z=20 ⑤
⑤-③,得
y=-1
把y=-1代入⑤中,得
z=1
把y=-1代入①中,得
x=2
∴{x=2 y=-1 z=1
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
{x+y+z=1 x-2y+3z=5 2x-3y-3z=-8
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
{x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
x/2=y/3=z/5 x+3y-z/x-3y+z
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