y=cos{α-π/2} .
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 00:22:52
y=cos{α-π/2}.y=cos{α-π/2}.y=cos{α-π/2}.y=cos{α-π/2}=cos{-【π/2-α】}=cos{π/2-α}=sinα
y=cos{α-π/2} .
y=cos{α-π/2} .
y=cos{α-π/2} .
y=cos{α-π/2}
=cos{-【π/2-α】}
=cos{π/2-α}
=sinα
y=cos{α-π/2} .
证明COS(X+Y)COS(X-Y)=COS^2X-SIN^2Y
证明cos(x+y)cos(x-y)= cos^2(x)-sin^2(y)
y=cos(π/3-x)cos[π/2(x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性
函数y=cosπ/2x×cosπ/2(x-1)的最小正周期
函数y=cosπ/2x×cosπ/2(x-1)的最小正周期
化简函数y=cos^2(x+7π/12)-cos^2(x+π/12),
函数y=cos^2(π/4-x)-cos^2(π/4+x)的值域是
y=cos【πx/2】cos【π(x-1)/2】的周期
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是:
y=cos(x+π/2)+cos的最大值怎么求?
求证1、sin l-sin y=2cos(l+y)/2 sin(l-y)/22、cos l+cos y=2cos(l+y)/2 cos(l+y)/23、cos l-cos y=-2sin (l+y)/2 sin (l-y)/24、tanatan2a/(tan2a-tana)+根号3(sin²a-cos²a)=2sin(2a-π/3)对了,还有:是否存在锐角l,y,
y=2cos x (sin x+cos x)
y=(cos x-2)/(cos x-1)的值域
y=cos^2 x-cos x +1的值域y=cos^2 x+cos x +1的值域,
函数y=sinα+cosα+2的最小值
y=sinα/(cosα+2)的值域