sin^2(α)+cos(30°-a)-sinacos(30°-a)=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 11:37:19
sin^2(α)+cos(30°-a)-sinacos(30°-a)=?sin^2(α)+cos(30°-a)-sinacos(30°-a)=?sin^2(α)+cos(30°-a)-sinacos(
sin^2(α)+cos(30°-a)-sinacos(30°-a)=?
sin^2(α)+cos(30°-a)-sinacos(30°-a)=?
sin^2(α)+cos(30°-a)-sinacos(30°-a)=?
sin²(a)+cos(30°-a)-sinacos(30°-a)
=sin²(a)+cos30°cosa+sin30°sina-sina(cos30°cosa+sin30°sina)
=sin²(a)+(√3/2)cosa+(1/2)sina-(√3/2)sinacosa-(1/2)sin²(a)
=(√3/2)cosa+(1/2)sina-(√3/2)sinacosa+(1/2)sin²(a)
=cos(30°-a)-sinacos(30°+a)
sin^2(α)+cos(30°-a)-sinacos(30°-a)=?
化简 sin^2 a+cos a*cos(60+a)-sin^(30-a)=
化简 sin^2 a+cos a*cos(60+a)-sin^(30-a)=
化简 (1+sin a+ cos a)(sin a/2 - cos a/2) / √(2+2cos a)(180°
sin/cos^2a+cos/sin^2a最小值
cosα+cos^2α=1求sin^2a+sin^6a+sin^8a=?
2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)mingbaidian
2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)
sin^4+sin^2cos^2+cos^2a=
sin(α+30°)-sin(α-30°)/cosα
求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
sin^2 30°+cos()=1
化简 sin(a+30°)+cos(a+60°) __________________________的结果是?2cos(360°-a)
已知 a为第二象限,证明:2sinαcosα/(sinα+cosα-1)(sinα+cosα+1)=(1+cosα)/sina
证明1-COS^2α/(SINα-COSα)-SINα+COSα/(TAN^2a-1)=SINa+COSa
求证:sin 2a/1+sin a+cos a=sin a+cos a-1急
化简sin(a+30)+cos(a+60)/2cosa
求值sin^2A+cos^2(A+30°)+sinAcos(A+30°)