化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 06:15:32
化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-18
化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
=-cosx×sinx/[-sin(180°+x)][cos(180°+x)]
=-cosx×sinx/sinx(-cosx)
=1
cos x/sin x+sin x/(1+cos x) 化简.
化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
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