硫化铅与氧气反应的方程式里面的电子得失情况2PdS+3O2=2PdO+2SO2how many electrons are lost by sulphur and gained by oxygen?A S lost 6 and 4 gainde OB S lost 0 and 4 gained OC S lost 6 and 2 gained OD S lost 8 and 4 gained OE none of
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硫化铅与氧气反应的方程式里面的电子得失情况2PdS+3O2=2PdO+2SO2how many electrons are lost by sulphur and gained by oxygen?A S lost 6 and 4 gainde OB S lost 0 and 4 gained OC S lost 6 and 2 gained OD S lost 8 and 4 gained OE none of
硫化铅与氧气反应的方程式里面的电子得失情况
2PdS+3O2=2PdO+2SO2
how many electrons are lost by sulphur and gained by oxygen?
A S lost 6 and 4 gainde O
B S lost 0 and 4 gained O
C S lost 6 and 2 gained O
D S lost 8 and 4 gained O
E none of the above
硫化铅与氧气反应的方程式里面的电子得失情况2PdS+3O2=2PdO+2SO2how many electrons are lost by sulphur and gained by oxygen?A S lost 6 and 4 gainde OB S lost 0 and 4 gained OC S lost 6 and 2 gained OD S lost 8 and 4 gained OE none of
硫化铅中的硫为-2价,二氧化硫中的硫为+4价,化学计量系数都是2,所以2个分子的硫化铅失去2*(4-(-2))=12,由于得失电子是守恒的,所以氧得到了12个电子,所以综合答案,选择D
solution: C
C 3个氧气分子得12个电子,那么一个氧原子就得2个电子;2个硫原子失12个电子,1个就失6个电子