1.An imaginary computer has eight data registers Rx(R0 to R7),16M words in memory,the address can address words in the 16M words memory,and have 32 different instructions (ADD,SUB,etc.).A typical instruction of the computer uses the following format:
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1.An imaginary computer has eight data registers Rx(R0 to R7),16M words in memory,the address can address words in the 16M words memory,and have 32 different instructions (ADD,SUB,etc.).A typical instruction of the computer uses the following format:
1.An imaginary computer has eight data registers Rx(R0 to R7),16M words in memory,the address can address words in the 16M words memory,and have 32 different instructions (ADD,SUB,etc.).A typical instruction of the computer uses the following format:SUB address,Rx
(1) What is the minimum size of an instruction in bits?
(2) If the instruction is in the minimum size and the computer uses the same size of word for data and instructions,what is the size of the data bus?
(3) What is the size of the program counter?
(4) What is the size of the address bus?
(5) What is the minimum size of the control bus?
1.An imaginary computer has eight data registers Rx(R0 to R7),16M words in memory,the address can address words in the 16M words memory,and have 32 different instructions (ADD,SUB,etc.).A typical instruction of the computer uses the following format:
一台假想的计算机有八个数据寄存器,标号是Rx（即R0~R7）,16M字节的内存,并能按字节寻址,有32条指令（加,减等）.这台计算机中典型的指令格式如下：
SUB address,Rx
即 指令名 地址,数据寄存器号
1.一条指令最少要多少位?
指令占5位：2^5=32;
地址占24位：2^4=16,计算机中2^10=1K,2^20=1M,所以16M=2^(20+4）;
寄存器占3位：2^3=8,也就是3位二进制数可以表示八个不同的寄存器.
因此一条指令所占用的最少位数=24+3+5=32
2.如果指令占用最小的位数（即32位）并且这台计算机用相同的字长来传输数据和指令（字长32位）,那么它的数据总线的宽度（32位,因为计算机一次处理一个字）
3.程序计数器（PC）的宽度
因为内存中有16M的地址单元,因此需要24位的程序计数器来表示.
4.地址总线的位数
24位,原因见上.
5.控制总线的最小宽度
1位（控制读或写操作）
不知道这是不是让你满意的答案
①如果说某计算机系统的字长为32bits，那意味着: 1. CPU通用数据总线的宽度为32bits 2. CPU内部数据寄存器位数为32bits； 3. 这台机器一次能做处理,