设函数f(x)=x*sin(1/x),x不等于0时；当x等于0时,f(x)=0 ,则在x=0处,函数为什么连续但不可导或者是连续可导，但是怎么证明

设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+∮)(-兀 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 1.设函数f(x)=sin(x+fai)(0 设函数f(x)=sin(2x+φ)(-π 设函数f (x)=cos(2x-π/3)-2sin平方x (1)求函数f(x 设f（x）={x^sin(1/x),x>0 a+e^x,x 设函数f(x)满足f(x)+2f(1/x)=x,求f(x)