a1=1 S(n+1)=4an+2求an通项

a1=1 S(n+1)=4an+2求an通项 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 数列{an}中,a1=1,an+1/an=n/n+2,求an a1=1,Sn=n^2an,求an a(n+1)=2an/3an+4,a1=1/4,求an a1=2,an+1=2/3an+n-4 求an 一道数学题、、数列{an}：a1=4,an=3an-1+2n-1,n≥2求an. an+1 ,n+1是下表 ,an+1=an^3 a1=2 ,求an a1=1/2,an+1=an/an+2,求n/an的sn 数列an集合中,a1=2,an+1=an+(2n+1),求an. 数列{an}中,a1=35,an+1-an=2n-1,求an 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 数列an,a1=4,an+1=5^n*an,求an用累乘法 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 已知{an}满足a1=1.an=3*n+2An-1,求an 数列a1=-1,an+1=2an+4*{3}^{n-1}a1=-1,an+1=2an+4*{3}^{n-1},求an 数列an中前n项和Sn,a1=4,n≥2时,an=[√Sn+√S(n-1)]/2,求an