a1=2,an+1=2/3an+n-4 求an

数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 一道数学题、、数列{an}：a1=4,an=3an-1+2n-1,n≥2求an. 数列a1=-1,an+1=2an+4*{3}^{n-1}a1=-1,an+1=2an+4*{3}^{n-1},求an a(n+1)=2an/3an+4,a1=1/4,求an a1=2,an+1=2/3an+n-4 求an an+1 ,n+1是下表 ,an+1=an^3 a1=2 ,求an 在数列an中,a1=2 an+1=an+3n则an= 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知{an}满足a1=1.an=3*n+2An-1,求an 数列{an}中,a1=2,an+1=4an-3n+1,求证{an-n}是等比数列 4an中n为下标an+1中n+1为下标an-n中an的n为下标 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列｛an｝中a1=1/2,a(n+1)=(2an)/(4an+3),求an. 数列A1=1/3,An+1=An+An²/n²求证An>1/2+1/4n改成An>1/2-1/4n不好意思 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列{an},a1=3,an*a(n+1)=(1/2)^n,求an 已知数列｛an｝中,a(n+1)=an+2^n,a1=3,求an 1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做 1、在数列{an}中,a1=1.a(n+1)=3an+2n+1.求an.2、在数列{an}中,a1=-1,a(n+1)=(3an-4)/[(an)-1].求an.