使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?

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使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?使(ax²-2x+y&su

使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?
使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?

使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?
(ax²-2xy+y²)-(-x²+bxy+2y²)
=ax²-2xy+y²+x²-bxy-2y²
=(a+1)x²-(2+b)xy-y²
=5x²-9xy+cy²
所以a+1=5
-(2+b)=-9
-1=c
所以
a=4,b=7,c=-1

a=4,b=7,c=-1

使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是? 因式分解:x ² - y²+ax+ay 因式分解 x²-y²-ay-ax 2a(x²+1)²-2ax²因式分解 a²-ab+ac-bc2ax-10ay+5by-bx3ax+4by+4ay+3bxm²+5m-mn-5nx²-y²+ax+aya²-2ab+b²-c²x³+x²y-xy²-y³4a²-b²+6a-3b9m²-6m+2n-n²x²-y²-z²+2yzx³-x²y-xy²+y³ (1) (m—n)²—n² (2)49(a-b)²—16(a+b)²(3) (2x+y)²—(x+2y)² (4) (x²+y²)²—x²y²(5)3ax²—3ay² 圆x²+y²=1与圆x²-2ax+a²+y²-4=0相切,求a的值? 求这几道因式分解的答案 a²-4a+4 4b²+4b-1 a²+ab+b² x²+12x+36 -2xy-x²-y² a²+2a+14x²+4x+1 ax²+2a²x+a3次方 -3x²+6xy-3y² 几道代数因式分解题1.3a(b²+9)²-108ab²2.3a(x²+4)²-48ax²3.x^4(a-2b)+x²y²(2b-a) 因式分解2a(X²+1)²-2AX² 1.(ax+by)²+(bx-ay)²2.(x²-x)²-4(x²-x-1)3.4(x+y)²-9(x-y)²4.(a+b)(a-b)+4(b-1)5.x²+4xy+4y²-2x-4y-36.(x+1)(x+2)(x+3)(x+4)+17,3x²-11x+10 求几道因式分解1.(ax+by)²+(bx-ay)²2.(x²-x)²-4(x²-x-1)3.4(x+y)²-9(x-y)²4.(a+b)(a-b)+4(b-1)5.x²+4xy+4y²-2x-4y-36.(x+1)(x+2)(x+3)(x+4)+17,3x²-11x+10 分解因式x²+14x+49 (m+n)²-6(m+n)+9 -x²-4y²+4xy -2xy-x²-y² 3ax²(a+b)²-12(a+b)+36 (x+y)²-4(x+y-1) 1-m²-n²+2mn要过程 是作业 急啊! 几道数学代数因式分解题1.1.1/2x²-8ax+32a²2.x²(x²-y²)+z²(y²-x²)3.5a²b(x-y)³-30ab²(y-x)² y²-6y-9x²+94x四次方-a²-6a-936-b²-c²+2bcax²+bx²-cx²+a+b-ca²-b²+2(ax-不用)+x²-y² 七年级因式分解题,要过程.1.x²(y²-9)+4(9-y²)2.(x-2y)²-3(x-2y)-103.6(x^n+1)+5(x^n)y-4(x^n-1)y²4.9-a²-b²+2ab5.x²-2xy+y²+4x-4y+46.(x+y)²-4(x+y+-1)7.(ax+by)²+(bx-ay)²8.(c-a)²-4(b-c 怎么算啊这个:X²+4X+Y²-2Y+5=0 则X²+Y²=?²²²²²²²²²²²²X²+4X+Y²-2Y+5X=0 则X²+Y²=? ax²+2xy-x-3x²-2bxy+3y 求a²-3b