(2x-3)*(2x+3)=16
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(2x-3)*(2x+3)=16(2x-3)*(2x+3)=16(2x-3)*(2x+3)=16(2X-3)(2X+3)=16==>(2X)^2-3^2=16==>4X^2=16+9==>4X^2=2
(2x-3)*(2x+3)=16
(2x-3)*(2x+3)=16
(2x-3)*(2x+3)=16
(2X -3)(2X +3) =16 ==> (2X)^2 -3^2 = 16 ==> 4X^2 = 16 + 9 ==> 4X^2 = 25 ==> X = 25/4 ==> X = 5/2,-5/2
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)
(x/x-2)-2=3(x-2)/x
x(2x-3)=x² 求x,
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解下列方程!就三道!解下列方程.1、x/x-2 - 1-x²/x²-5x = 2x/x-3(x/x-2 - 1-x²不是一起的!)2、5x/x²+x-6 - 5-2x/x²-x-12=7x-10/x²-6x+8(5x/x²+x-6 - 5-2x不是一起的!)3、x-4/x-5 + x-8/x-9=x-7/x-
1.(x+1)(2x-3)-(x-1)(x+2)=x.x+71.(x+1)(2x-3)-(x-1)(x+2)=x.x+72.(2x+1)(4x.x-2x+1)-2x(4x.x+1)=03.(x-3)(x+2)=x.x-16
(1)(2x/x-1)-(x-1/x)=1 (2)(x^2-4x/x^2-1)+1=2x/x+1 (3)(x+4/x^2+2x)-(1/x+2)=(2/x)+1
(1)(2x/x-1)-(x-1/x)=1 (2)(x^2-4x/x^2-1)+1=2x/x+1 (3)(x+4/x^2+2x)-(1/x+2)=(2/x)+1
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当x=根号3/3,代数式[(x*x-3x)/x]除以[x+(3/2-x)]
2x-6/4-4x+x^2/(x+2)*x^2-4/3-x,其中x=-1