cos(arccos1除以根号x)求导

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cos(arccos1除以根号x)求导cos(arccos1除以根号x)求导cos(arccos1除以根号x)求导y=cos(arccos(1/√x))y''=-sin(arccos(1/√x)).(a

cos(arccos1除以根号x)求导
cos(arccos1除以根号x)求导

cos(arccos1除以根号x)求导
y= cos(arccos(1/√x) )
y' = -sin(arccos(1/√x)) .(arccos(1/√x))'
= -sin(arccos(1/√x)) .(-1/√(1-x^2) )(1/√x))'
=-sin(arccos(1/√x)) .(-1/√(1-x^2) )(-(1/2)(x)^(-3/2)
=-sin(arccos(1/√x)) /[2x^(3/2) .√(1-x^2) ]