已知x+y+z=0,求x4+y4+z4-2x2y-2y2z2-2z2x2的值有指数

已知x+y+z=0,求x4+y4+z4-2x2y-2y2z2-2z2x2的值有指数 已知x+y+z=0,x2+y2+z2=1,求xy+yz+xz,x4+y4+z4的解数字为平方和四次方, 已知x+y+z=1 x2+y2+z2=2 x3+y3+z3=3 求x4+y4+z4=? x,y,z属于正实数,求证:x4+y4+z4>=(x+y+z)xyz4是4次方 x+y+z=3,x2+y2+z2=29,x3+y3+z3=45,求xyz和x4+y4+z4的值 x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,x4+y4+z4=? 因式分解：(x+y+z)4-(y+z)4-(z+x)4-(x+y)4+x4+y4+z4, 已知X+Y+Z=0,X平方+Y平方+Z平方=1求XY+YZ+XZ和X4次方+Y4次方+ZY4次方的值? 证明;x4+y4+z4-2x2y2-2x2y2-2y2z2能被（x+y+z）整除 实数 x y z 满足 x+y+z=1 x²+y²+z²=3 x³+y³+z³x4+y4+z4=?快 用MATLAB或VB解四元二次方程组最好用牛顿迭代法(x1-x)^2+(y1-y)^2+(z1-z)^2-(t1-t)^2=0(x2-x)^2+(y2-y)^2+(z2-z)^2-(t2-t)^2=0(x3-x)^2+(y3-y)^2+(z3-z)^2-(t3-t)^2=0(x4-x)^2+(y4-y)^2+(z4-z)^2-(t4-t)^2=0求x、y、z、t 证明:x4+y4+z4-2x2y2-2x2z2-2y2z2能被x+y+z整除八年级寒假作业题目 已知x-y=1,求代数式x4-xy3-x3y-3x2y+3xy2+y4 三元二次方程组怎么解啊?f1=(x-x1)^2+(y-y1)^2+(z-z1)^2-r1(i)^2=0;f2=(x-x2)^2+(y-y2)^2+(z-z2)^2-r2(i)^2=0;f3=(x-x3)^2+(y-y3)^2+(z-z3)^2-r3(i)^2=0;f4= (x-x4)^2+(y-y4)^2+(z-z4)^2-r4(i)^2=0; 有没有x3+y3=z3,x4+y4=z4,x5+y5=z5和x6+y6=z6甚至xn+yn=zn?4,5,6,n都在x,y,z的右上方.xyz可以是非0的整数,0,或者是分数.如果有的话就举一两个例子. 已知：x-y+1=0,xy-2x-2y-7=0,求x2+y2以及4x2y2-x4-y4. 已知x-y=1,x3-y3=2,求x4+y4及x5-y5的值.各路神通, 已知x=2,y=-3,求（x4次方-y4次方）除以x+y分之x平方+y平方的值__-----要过程