讲教一下师傅隐函数求导sinxy-ln(x+y)=0sinxy-ln(x+y)=0两边对X求导解:cos(xy)(y+xy')-(1+y)/(x+y)=0其中cos(xy)(y+xy')怎么得来的?要详细步骤(初学请谅解!谢谢!)隐函数y怎么处理呀?回答的好有追加分!

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/23 17:16:30
讲教一下师傅隐函数求导sinxy-ln(x+y)=0sinxy-ln(x+y)=0两边对X求导解:cos(xy)(y+xy'')-(1+y)/(x+y)=0其中cos(xy)(y+xy'')怎么得来的?要

讲教一下师傅隐函数求导sinxy-ln(x+y)=0sinxy-ln(x+y)=0两边对X求导解:cos(xy)(y+xy')-(1+y)/(x+y)=0其中cos(xy)(y+xy')怎么得来的?要详细步骤(初学请谅解!谢谢!)隐函数y怎么处理呀?回答的好有追加分!
讲教一下师傅隐函数求导sinxy-ln(x+y)=0
sinxy-ln(x+y)=0两边对X求导
解:cos(xy)(y+xy')-(1+y)/(x+y)=0
其中cos(xy)(y+xy')怎么得来的?要详细步骤(初学请谅解!谢谢!)隐函数y怎么处理呀?回答的好有追加分!

讲教一下师傅隐函数求导sinxy-ln(x+y)=0sinxy-ln(x+y)=0两边对X求导解:cos(xy)(y+xy')-(1+y)/(x+y)=0其中cos(xy)(y+xy')怎么得来的?要详细步骤(初学请谅解!谢谢!)隐函数y怎么处理呀?回答的好有追加分!
这里用隐函数求导是因为很难将x分离出来,变成y=f(x)的形式.故先把y看成关于x的函数.
(sinxy)'=cos(xy)(xy)'=cos(xy)(x'y+xy')
=cos(xy)(y+xy')