设y=e^x-lncosx,求dy
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设y=e^x-lncosx,求dy设y=e^x-lncosx,求dy设y=e^x-lncosx,求dydy=[e^x-(1/cosx)(-sinx)]dx=[e^x+tanx]dx
设y=e^x-lncosx,求dy
设y=e^x-lncosx,求dy
设y=e^x-lncosx,求dy
dy=[e^x-(1/cosx)(-sinx)]dx=[e^x+tanx]dx
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