设y=x乘以根号x+lncosx,求dy,
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/23 04:12:16
设y=x乘以根号x+lncosx,求dy,设y=x乘以根号x+lncosx,求dy,设y=x乘以根号x+lncosx,求dy,y=x乘以根号x+lncosx=x^(3/2)+lncosxy''=3/2√
设y=x乘以根号x+lncosx,求dy,
设y=x乘以根号x+lncosx,求dy,
设y=x乘以根号x+lncosx,求dy,
y=x乘以根号x+lncosx
=x^(3/2)+lncosx
y'=3/2 √x +1/cosx· (-sinx)
=3√x /2 -tanx
dy=(3√x /2 -tanx)dx
设y=x乘以根号x+lncosx,求dy,
设y=x√x＋lncosx,求dy
设Y=e的X次方-lncosx 求dy
设y=e^x-lncosx,求dy
设y= ex- lncosx 求dy
设y=e的x平方减lncosx,求dy
y=lncosx,求dy
y=lncosx 求dy
y=ex2-lncosx 求dy
设y=e的根号x 求dy
设y=arctan根号x,求dy
设y=e平方减lncosx,求dy.求全过程
设y=根号下[x+(根号x)],求dy（1）=?
设y=arctan根号(x^2-1)-lnx/根号(x^2-1)求dy
Y=lncosx-cose 求：Y设Y=x³lnx求：y23设f(x)=(1+cos)x 求f'(x)
设y=(lnx)/x,求dy?
y=lncosx,求dy/dx;f'(x)=3x平方,且f(0)=1,则f(x)=
设函数y=x的平方乘以sinx,求dy