a(x-y)^2n-b(y-x)^2n+1（分解因式）还有几题 好心人帮我一起回答了吧：（a-b）²（a＋b）³-（b-a）²（b＋a）² 2（a-b）²-a＋b -x²（m-n）^5-xy（n-m）³ 35ab（x-y

(x+y+z)^2-(x-y-z)^2(a-b)^n+2 -(a-b)^n y^2-9(x+y)^2.a(x-y)-b(y-x)+c(x-y)..x（m+n)-y(n+m)+(m+n)..(x+y)^2-16(x-y)^2因式分解 m(x-y)^n+n(y-x)^2n因式分解 已知a,b,x,y都是实数,n∈N,x+yi=(a+bi)^n,求证：x^2+y^2=(a^2+b^2)^n 因式分解:a(x-y)的n次方-3b(y-x)的n+1次方+2c(y-x)的n+2次方(n为正整数) A={y|y=x2-4x+6,y属于N},B={y|y=-x2-2x+18,y属于N},求A交B. 假设集合U={(x,y)|x∈R,y∈R },A={(x,y)|2x-y+m>0},B={(x,y)|x+y-n x^n*y*(-x^2y^m) x^2y(a-b)^2n+xy^2(b-a)^2n+1因式分解 分解因式：x（a-b）2n次方+y (b-a)2n+1次方 x(a-b)*2n+y(b-a)*2n-1 怎么因式分解, x(a-b)的2n次方+y(b-a)的2n-1次方=? 因式分解 ；(x-y)平方-(y-x)平方 a(x-y)n次方-3b(y-x)n+1次方+2c(y-x)n+2次方(n为正整数) 12xy(m-n)-x的平方（n-m)的平方x(x-2y)(a-b)-y(2y-x)(b-a)、、、、、、、、、、？ matlab利用递归求解差分方程function y = recur(a,b,n,x,x0,y0);%% y = recur(a,b,n,x,x0,y0)% solves for y[n] from:% y[n] + a1*y[n-1] + a2*y[n-2]...+ an*y[n-N]% = b0*x[n] + b1*x[n-1] + ...+ bm*x[n-M] %% a,b,n,x,x0 and y0 are vectors% a = [a1 a2 y-n = - (a-m)(x-m)/(b-n) .(1) (x-m)^2+(y-n)^2 = L^2 .(2) 求X,Y的值 若n是正整数,有理数x、y满足x+y分之一=0,则一定成立的是 A.x^2n+1+(1/y)^n=0 B.x^2n+1+(1/y)^2n+1=0C.x^2n+(1/y)^2n=0 D.x^n+(1/y)^2n=0 y=x^2/(a^2-b^2 *x^2) 求y的n阶导数