n²+n²(n+1)²+(n+1)²2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/28 20:17:01
n²+n²(n+1)²+(n+1)²2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²

n²+n²(n+1)²+(n+1)²2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²
n²+n²(n+1)²+(n+1)²
2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²

n²+n²(n+1)²+(n+1)²2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²
n²+n²(n+1)²+(n+1)²=[n(n+1)]²+2n²+2n+1=[n(n+1)]²+2n(n+1)+1=[n(n+1)+1]²=(n²+n+1)²
2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²=(a²-b²)²+(b²-c²)²+(a²-c²)²

n²+n²(n+1)²+(n+1)²=[n(n+1)]²+2n²+2n+1=[n(n+1)]²+2n(n+1)+1=[n(n+1)+1]²=(n²+n+1)²
2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c...

全部展开

n²+n²(n+1)²+(n+1)²=[n(n+1)]²+2n²+2n+1=[n(n+1)]²+2n(n+1)+1=[n(n+1)+1]²=(n²+n+1)²
2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c²=(a²-b²)²+(b²-c²)²+(a²-c²)²

收起

(1)n^2+n^2*(n+1)^2+(n+1)^2
=n^2+n^2(n+1)*(n+1)+(n+1)^2
=n^2+n^3(n+1)+n^2(n+1)+(n+1)^2
=n^4+n^2(n+1)+n^2(n+1)+(n+1)^2
=(n^2+n+1)^2
2a^4+2b^4+2c^4-2a²b²-2b²c²-2a²c
=(a²-b²)²+(b²-c²)²+(a²-c²)²望采纳o(∩_∩)o...