x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1
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x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1x/x^2+x+1=-1/22x^2/(x^2-
x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1
x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1
x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1
x/(x^2+x+1)=-1/2
x^2+x+1=-2x
则x^2-x+1=-4x
且x^2+1=-3x
2x^2/(x^2-x+1)+(x-1)/(x^3-1)
=2x^2/(x^2-x+1)+(x-1)/(x-1)(x^2+x+1)
=2x^2/(x^2-x+1)+1/(x^2+x+1)
=2x^2/(-4x)+1/(-2x)
=-x/2-1/2x
=-(x^2+1)/2x
=-(-3x)/2x
=3/2
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x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x/x平方-x+2=2x/x+1
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
(X+1)X(X+2)X(X+3)=504
x/x^2+x+1=-1/22x^2/(x^2-x+1)+x-1/x^3-1
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一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
(4x+2)/x+(4x-22)/(x-5)=(x-6)/(x-4)+(7x+9)/(x+1)
分解因式----(X*X-X)(X*X-X-2)+1
】x(x+1)+x^2(x-1)
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
(x/x-2)+(2/x*2+2x)-(x+6/x*2-4)化简,=x^2/x(x-2)+(2x-4)/x(x^2-4)-(x^2+6x)/x(x^2-4)=x^2/x(x-2)-(x+2)/x(x-2)=(x-2)(x+1)/x(x-2)=(x+1)/x
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
x(x-2)-2x(x+1)-3x(x-5) 其中x=负½
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
如果X*X--1=0,那么X*X*X+2*X*X+2008=几?