2 2 2 2已知Ia+1l与l2a+bl互为相反数,试求整式3{a-b} -5{a-b} +3{a+b}+{a-b} -7{a+b} -3(a+b}的值.已知x+y= -4,xy=3,求4(xy+2y)+{6x-(2xy-y-3x)}的值.

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 19:44:00
2222已知Ia+1l与l2a+bl互为相反数,试求整式3{a-b}-5{a-b}+3{a+b}+{a-b}-7{a+b}-3(a+b}的值.已知x+y=-4,xy=3,求4(xy+2y)+{6x-(

2 2 2 2已知Ia+1l与l2a+bl互为相反数,试求整式3{a-b} -5{a-b} +3{a+b}+{a-b} -7{a+b} -3(a+b}的值.已知x+y= -4,xy=3,求4(xy+2y)+{6x-(2xy-y-3x)}的值.
2 2 2 2
已知Ia+1l与l2a+bl互为相反数,试求整式3{a-b} -5{a-b} +3{a+b}+{a-b} -7{a+b} -3(a+b}的值.
已知x+y= -4,xy=3,求4(xy+2y)+{6x-(2xy-y-3x)}的值.

2 2 2 2已知Ia+1l与l2a+bl互为相反数,试求整式3{a-b} -5{a-b} +3{a+b}+{a-b} -7{a+b} -3(a+b}的值.已知x+y= -4,xy=3,求4(xy+2y)+{6x-(2xy-y-3x)}的值.
1) 由题意得:
Ia+1l+l2a+bl=0
∴a+1=0 2a+b=0
∴a=-1 b=2
3{a-b} -5{a-b} +3{a+b}+{a-b} -7{a+b} -3(a+b}
=(a-b)*(3-5+1)+(a+b)*(3-7-3)
=(a-b)(-1)+(a+b)(-7)
将a=-1 b=2代入原式
原式=-3*-1+1*-7
=-4
2)4(xy+2y)+{6x-(2xy-y-3x)}
=4xy+8y+(6x-2xy+y+3x)
=4xy+8y+6y-2xy+y+3x
=9(x+y)+2xy
=9*(-4)+2*3
=-30

sorry