数列{an}满足an+1= -2an+( -2)的n+1次方,首项为a1= -2,求数列{an}的通项公式
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数列{an}满足an+1=-2an+(-2)的n+1次方,首项为a1=-2,求数列{an}的通项公式数列{an}满足an+1=-2an+(-2)的n+1次方,首项为a1=-2,求数列{an}的通项公式
数列{an}满足an+1= -2an+( -2)的n+1次方,首项为a1= -2,求数列{an}的通项公式
数列{an}满足an+1= -2an+( -2)的n+1次方,首项为a1= -2,求数列{an}的通项公式
数列{an}满足an+1= -2an+( -2)的n+1次方,首项为a1= -2,求数列{an}的通项公式
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按照你所给的题目算出来跟已知矛盾,建议你再检查一下题目。是{an+1= -2[a(n+1)]+( -2)的n+1次方}吧???
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