Sn是等差数列{an}的前n项和,已知a2=3,a6=11则S7等于几选项A 13 B 35 C 49 D 63
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Sn是等差数列{an}的前n项和,已知a2=3,a6=11则S7等于几选项A13B35C49D63Sn是等差数列{an}的前n项和,已知a2=3,a6=11则S7等于几选项A13B35C49D63Sn
Sn是等差数列{an}的前n项和,已知a2=3,a6=11则S7等于几选项A 13 B 35 C 49 D 63
Sn是等差数列{an}的前n项和,已知a2=3,a6=11则S7等于几
选项A 13 B 35 C 49 D 63
Sn是等差数列{an}的前n项和,已知a2=3,a6=11则S7等于几选项A 13 B 35 C 49 D 63
a2+a6=a1+a7
S7=(a1+a7)*7/2=(a2+a6)*7/2=49
这里有个关系是
Am+Am=Ap+Aq 条件为m+n=p+q
a6 = a2 + 4d
11 = 3 + 4d
d = 2
a1 = a2 - d = 1
a7 = a6 + d = 13
S7 = (1 + 13)×7÷2 = 49
所以选 C
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