(xy-6)2+/x+y-5/=0 求x2+y2的值
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(xy-6)2+/x+y-5/=0求x2+y2的值(xy-6)2+/x+y-5/=0求x2+y2的值(xy-6)2+/x+y-5/=0求x2+y2的值因为(xy-6)平方大于等于0,x+y-5的绝对值
(xy-6)2+/x+y-5/=0 求x2+y2的值
(xy-6)2+/x+y-5/=0 求x2+y2的值
(xy-6)2+/x+y-5/=0 求x2+y2的值
因为(xy-6)平方大于等于0,x+y-5的绝对值也大于等于0.所以xy-6=0且x+y-5=0时整个式子才会等于0,所以xy=6,x+y=5,x平方+y的平方=(x+y)的平方-2xy=25-12=13
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