f(x)=ln(x+1)-kx/(x+1)(k为常数).(1)求f(x)的单调区间(2)证明不等式:x/ln(x+1)-1

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 21:54:37
f(x)=ln(x+1)-kx/(x+1)(k为常数).(1)求f(x)的单调区间(2)证明不等式:x/ln(x+1)-1f(x)=ln(x+1)-kx/(x+1)(k为常数).(1)求f(x)的单调

f(x)=ln(x+1)-kx/(x+1)(k为常数).(1)求f(x)的单调区间(2)证明不等式:x/ln(x+1)-1
f(x)=ln(x+1)-kx/(x+1)(k为常数).
(1)求f(x)的单调区间
(2)证明不等式:x/ln(x+1)-1

f(x)=ln(x+1)-kx/(x+1)(k为常数).(1)求f(x)的单调区间(2)证明不等式:x/ln(x+1)-1
变形:x/ln(x+1)-12
令F(x)=ln(x+1)+4/(x+2)
求导 F'(x)=1/(x+1) -4/(x+2)^2
=x^2/[(x+1)·(x+2)^2]>0
(0