-64*[-2(-1/4+1/6)+81/(-27/8)
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-64*[-2(-1/4+1/6)+81/(-27/8)-64*[-2(-1/4+1/6)+81/(-27/8)-64*[-2(-1/4+1/6)+81/(-27/8)-64*[-2(-1/4+1/6
-64*[-2(-1/4+1/6)+81/(-27/8)
-64*[-2(-1/4+1/6)+81/(-27/8)
-64*[-2(-1/4+1/6)+81/(-27/8)
-64*[-2(-1/4+1/6)+81/(-27/8)]
=-64*[(1/2-1/3)-24]
=-64*1/6+64*24
=-32/3+1536
=1525+1/3
-64*[-2(-1/4+1/6)+81/(-27/8)]
=128(-1/4+1/6)+64*81/(-27/8)
=128*(-1/12)+64*24
=-32/3+1536
=1525+1/3
-64*[-2(-1/4+1/6)+81/(-27/8)
1,4,9,16,25,( ),( ),64,81
1,4,9,16,25?64,81
81,64,(),36,(),16,9,4,1
81 64 49_25_9 4 1
81,64,49,(),25,(),9,4,(),1
81,64,49,36,( ),( ),9,4,11,1,2,3,5,8,( ),( )2,3,6,18,( ),( )96,48,24,( ),( ).
找规律填空：1/6、1/4、3/8、（）、（）、81/64
1/2,3/4,8/9,( ),81/32,( ),( ) 27/64,9/16,3/4,( ),( ) 找规律
100,81,64,(),36,25,(),9,4,1这2个括号怎么填
1,32,81,64,25,( ),1A.5 B.6 C.10 D.12-2,-8,0,64,( A.-64 B.128 C.156 D.250
数字推理：一、64,48,36,27,81/4,( )A.97/6 B.123/38 C.179/12D.243/16 二、2187,729,81,3,( )A.1/81 B.1/27 C.1/9 D.1三、1,2,4,4,1,( )A.16 B.17 C.1/32 D.1/16第二三书上答案是B C
怎样求这个行列式的值1 1 1 1 2 4 8 164 16 64 2563 9 27 81
填空:81 ,64 ,49 ,36,(),(),9 ,4 ,1写出规律
9=81,8=64,7=49,6=36,5=25,4=?,3=?,2=?1=?
找规律,再计算.1/2+1/4+1/81/2+1/4+1/8+1/161/2+1/4+1/8+1/16+1/321/2+1/4+1/8+1/16+1/32+1/64
1 32 81 64 25 ( ) 1
1,32,81,64,25,6,1,1/8 隔项,是否有规律