数列an满足a1=1,an=1/2a(n-1)+1(n≥2) (1)若bn=an-2,求证bn为等比数列 (2)求an的通项公式
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数列an满足a1=1,an=1/2a(n-1)+1(n≥2)(1)若bn=an-2,求证bn为等比数列(2)求an的通项公式数列an满足a1=1,an=1/2a(n-1)+1(n≥2)(1)若bn=a
数列an满足a1=1,an=1/2a(n-1)+1(n≥2) (1)若bn=an-2,求证bn为等比数列 (2)求an的通项公式
数列an满足a1=1,an=1/2a(n-1)+1(n≥2) (1)若bn=an-2,求证bn为等比数列 (2)求an的通项公式
数列an满足a1=1,an=1/2a(n-1)+1(n≥2) (1)若bn=an-2,求证bn为等比数列 (2)求an的通项公式
1,an=1/2a(n-1)+1,an-2=1/2[a(n-1)-2],bn=1/2b(n-1),所以bn为等比为2的等比数列 ;
2,b1=a1-2=1-2=-1,
所以bn=-1(1/2)^(n-1)=-(1/2)^(n-1),所以an=bn+2=2-(1/2)^(n-1).
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