计算∫(4x-6)/(x^2-3x+9)dx,
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 05:25:11
计算∫(4x-6)/(x^2-3x+9)dx,计算∫(4x-6)/(x^2-3x+9)dx,计算∫(4x-6)/(x^2-3x+9)dx,∫(4x-6)/(x²-3x+9)dx=2∫(2x-
计算∫(4x-6)/(x^2-3x+9)dx,
计算∫(4x-6)/(x^2-3x+9)dx,
计算∫(4x-6)/(x^2-3x+9)dx,
∫(4x-6)/(x²-3x+9)dx
=2∫(2x-3)/(x²-3x+9)dx
=2∫1/(x²-3x+9)d(x²-3x)
令x²-3x=t
则
=2∫1/(t+9)dt
=2∫1/(t+9)d(t+9)
=2ln(t+9)+c
=2ln(x²-3x+9)+c
∫(4x-6)/(x^2-3x+9)dx,
=4ʃ(x-3/2)/[(x-3/2)²+27/4] dx
=2ʃ d[(x-3/2)²+27/4]/[(x-3/2)²+27/4]
=2ln|(x-3/2)²+27/4|+C
=2ln(x^2-3x+9)+C
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算:x+2/x-3×x²-6x+9/x²-4
计算:(x^2+6x+10)/(x^2+6x+9)+(x^2-11)/(x^2-9)+(2x^2+8x+5)/(x^2+4x+3)
计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9)
x/x-3-5x/x^2-x-6计算
计算:x/x-2 - 5x/x²-x-6计算:x/x-3 - 5x/x²-x-6
2x*4x-3x计算
计算:x^2-9/4-x^2*x^2+x-2/x^2-4x+3,
计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9
x^2+x-6分之x^2+3x-x^2-4分之x+2计算
计算:(-x^4)^3-(x^2)^6
计算分式2x-4/x²+3x÷x-2/x²+6x+9
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
计算∫(4x-6)/(x^2-3x+9)dx,
计算3x^4-6x^3+9x^2÷(-3x)
计算:2/3√9x - 6√x/4 + 2x/√x
计算(x^2-6x+9)÷(x-3)
-3x-[4x-(-9x+½)-2]求计算