已知|a+b-c|+|b-1|=-|2-ab|求1/abc+1/(a+1)(b+1)(c+1)+1/(a+2)(b+2)(c+2)+……1/(a+97)(b+97)(C+97)=

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已知|a+b-c|+|b-1|=-|2-ab|求1/abc+1/(a+1)(b+1)(c+1)+1/(a+2)(b+2)(c+2)+……1/(a+97)(b+97)(C+97)=已知|a+b-c|+|

已知|a+b-c|+|b-1|=-|2-ab|求1/abc+1/(a+1)(b+1)(c+1)+1/(a+2)(b+2)(c+2)+……1/(a+97)(b+97)(C+97)=
已知|a+b-c|+|b-1|=-|2-ab|求1/abc+1/(a+1)(b+1)(c+1)+1/(a+2)(b+2)(c+2)+……1/(a+97)(b+97)(C+97)=

已知|a+b-c|+|b-1|=-|2-ab|求1/abc+1/(a+1)(b+1)(c+1)+1/(a+2)(b+2)(c+2)+……1/(a+97)(b+97)(C+97)=
稍等哈