Chem homework please help~Chem homework please help~

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Chemhomeworkpleasehelp~Chemhomeworkpleasehelp~Chemhomeworkpleasehelp~Chem homework please&

Chem homework please help~Chem homework please help~
Chem homework please help~
Chem homework please help~

Chem homework please help~Chem homework please help~

先分析题目，根据氧化物M2O可以判断M2O中M是+1价，

然后可以写出反应式2M2O(受热)==4M+O2↑

  1. 解答① 检验氧气的方法，书本上面最常用的就是利用氧气的助燃性【将带有火星的木条，伸入装有氧气的瓶口，若木条复燃，则检验为氧气】

  2. 解答②根据上面的化学方程式2M2O(受热)==4M+O2↑

    可以得知，每当有1份(mol)氧气因受热分解出来，和4份(mol)M单质生成，就会有2份(mol)该氧化物受热分解

    2M2O~~~~2份(mol)共3.48g

    M~~~~~~~4份(mol)共3.24g~~~~~~~~~~~~~4份(mol)×相对分子质量m

    O2~~~~~~1份(mol)共3.48-3.24=0.24g~~~~1份(mol)×相对分子质量32

    因为3.24:m=0.24:32

    4m=3.24×32÷0.24=432

    m=108

    查元素周期表知道m为银(Ag)

  3. 解答③【图片我看不太清楚，看着像稀氢氯酸】不能和稀氢氯酸反应，因为银的金属活动性比氢差。

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