(2x-1)(1-x)/x+2≥0与4-x²/x²-2x-8≤0怎么解

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 通分（x+2)/(x^2-2x)与(x-1)/(x^2-4x+4) 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做 x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 通分x/(2+2x)与1/(x^2-x) 通分1/x^2-4与x/4-2x (2x-1)(1-x)/x+2≥0与4-x²/x²-2x-8≤0怎么解 比较(x-1)(x+4)与(x+3)(x-2)+2x的大小 三角函数与微积分相关对于x > 0,证明：x/(1+x^2) < arctan(x) < x 通分 1/x²-4与x/4-2x x/(x-1)²与1/x²-1 用MATLAB求解以下优化问题设计变量：X = {x1,x2 ,x3 ,x4}T约束条件：g1( X )=-x(1)* x(1)-x(2)* x(2)- x(3)* x(3)- x(4)* x(4)- x(1)+ x(2)- x(3)+x(4)+9≥0g2( X )=-x(1)*x(1)-2*x(2)*x(2)-x(3)*x(3)-2*x(4)*x(4)+x(1)+x(4)+8≥0g3( X )= -2*x(1) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 设f (x)={2x+1(x≥0),x²+4(x 已知f(x)=x^2-1,g(x)=x-1(x小于0)或2-x(x大于0),求f[g(x)]与[f(x)] 求证：多项式（x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)的值与x的取值无关 解分式不等式(x+2)/(x+1)+(x+3)/(x+2)≥(x+1)/x+(x+4)/(x+3) 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值