sin(派/6-x)=3/7,则cos(2派/3-x)=?

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sin(派/6-x)=3/7,则cos(2派/3-x)=?sin(派/6-x)=3/7,则cos(2派/3-x)=?sin(派/6-x)=3/7,则cos(2派/3-x)=?cos(2π/3-x)=-

sin(派/6-x)=3/7,则cos(2派/3-x)=?
sin(派/6-x)=3/7,则cos(2派/3-x)=?

sin(派/6-x)=3/7,则cos(2派/3-x)=?
cos(2π/3-x)=-cos[π-(2π/3-x)]
=-cos(π/3+x)
=-sin[π/2-(π/3+x)]
=-sin(π/6-x)
=-3/7