a.the sum of the forces (合力)b.the sum of their moments about point Q (所有力在Q的力偶之和)c.the moment of the forces about the y axis (y轴的力偶)若是把它们拆成沿x,y,z轴的力,每个分力都会有力矩, 那不是要算15次
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a.thesumoftheforces(合力)b.thesumoftheirmomentsaboutpointQ(所有力在Q的力偶之和)c.themomentoftheforcesabouttheya
a.the sum of the forces (合力)b.the sum of their moments about point Q (所有力在Q的力偶之和)c.the moment of the forces about the y axis (y轴的力偶)若是把它们拆成沿x,y,z轴的力,每个分力都会有力矩, 那不是要算15次
a.the sum of the forces (合力)
b.the sum of their moments about point Q (所有力在Q的力偶之和)
c.the moment of the forces about the y axis (y轴的力偶)
若是把它们拆成沿x,y,z轴的力,每个分力都会有力矩, 那不是要算15次力矩?
(上面的题目是力矩不是力偶,我打错了)
a.the sum of the forces (合力)b.the sum of their moments about point Q (所有力在Q的力偶之和)c.the moment of the forces about the y axis (y轴的力偶)若是把它们拆成沿x,y,z轴的力,每个分力都会有力矩, 那不是要算15次
把力从其作用点拆成沿各轴的力再加减,沿力作用方向移动不产生力偶,垂直作用方向需要增加相应力偶 给你个思路 图用电脑画太恶心了
拆了以后先能抵消的抵消掉
for the sum of 16 EPA listed PAHs
The limitis the limit of a right Riemann sum for a certain definite integralusing a partition of the interval into subintervals of equal length,wheref(x) =
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“The sum of the measures in degrees of the angles of a triangle is 180.The sum of the measures in degrees of the angles of a triangle is 180.= =偶被搞晕了.
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What is the sum of angles on one side of a straight line?