等差数列中

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 02:03:19
等差数列中等差数列中 等差数列中h分共和国放假擐甲挥戈a1=5/6a(n+1)=(1/3)an+(1/2)^(n+1)a(n+1)-3(1/2)^(n+1)=(1/3)[an-3(1/2)^

等差数列中
等差数列中
 

等差数列中

h分共和国放假擐甲挥戈

a1=5/6
a(n+1)= (1/3)an + (1/2)^(n+1)
a(n+1) -3(1/2)^(n+1) = (1/3)[an -3(1/2)^n]
{an -3(1/2)^n}是等比数列,q=1/3
an -3(1/2)^n = (1/3)^(n-1).(a1 -3(1/2))
= -2(1/3)...

全部展开

a1=5/6
a(n+1)= (1/3)an + (1/2)^(n+1)
a(n+1) -3(1/2)^(n+1) = (1/3)[an -3(1/2)^n]
{an -3(1/2)^n}是等比数列,q=1/3
an -3(1/2)^n = (1/3)^(n-1).(a1 -3(1/2))
= -2(1/3)^n
an =3(1/2)^n -2(1/3)^n
bn= 2^n.an
= 3 - 2(2/3)^n
Sn =b1+b2+...+bn
= 3n - 2[ (2/3)[ 1- (2/3)^n] / (1-2/3) ]
= 3n - 4[ 1- (2/3)^n ]

收起