2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
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2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0求方程组的解2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0求方程组的解2x-5+y/3=x+3
2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
由2x-5+y/3=x+3y/4+7 得
x-5/12y-12=0
12x-5y -144=0 (1)
由10(x-y)-4(1-x)/3-y=0 得
34/3x-11y-4/3=0
34x-33y-4=0 (2)
(1)*33-(2)*5
226x-4732=0
x=2366/113
代入 (1)式可解得
y=2424/113.
kojiouiouji
化简为12x-5y-144=0,34x-33y-4=0,解得x=4260/226,y=11448/565
式子没错?为什么算不出整数?
解第一个方程得 x=5y/12+12,将第二个方程化简得34x-33y=4,将 x=5y/12+12带入到34x-33y=4得y=143/2424,x=29803/29088
我所算出的化简也为12x-5y-144=0,34x-33y-4=0,并且答案也不是整数,但是答案是x=2366/113,y=2424/113.
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x=4
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