x^2+2x+y^2-6y+10=0,求x和y的值

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x^2+2x+y^2-6y+10=0,求x和y的值x^2+2x+y^2-6y+10=0,求x和y的值x^2+2x+y^2-6y+10=0,求x和y的值把10拆成1+9(x²+2x+1)+(y

x^2+2x+y^2-6y+10=0,求x和y的值
x^2+2x+y^2-6y+10=0,求x和y的值

x^2+2x+y^2-6y+10=0,求x和y的值
把10拆成1+9
(x²+2x+1)+(y²-6y+9)=0
(x+1)²+(y-3)²=0
平方大于等于0,相加等于0
若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以x+1=0,y-3=0
所以x=-1,y=3

x^2+2x+y^2-6y+1+9=0
(x^2+2x+1)+(y^2-6y+9)=0
(x+1)^2+(y-3)^2=0
x=-1
y=3

x^2+2x+y^2-6y+10=（x+1）^2+（y-3）^2=0
那么x=-1，y=3

x=-1,y=3.

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