x+log[2,(2^x-31)]=5log[2,(2^x-31)]底数2真数2^x -31
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x+log[2,(2^x-31)]=5log[2,(2^x-31)]底数2真数2^x-31x+log[2,(2^x-31)]=5log[2,(2^x-31)]底数2真数2^x-31x+log[2,(2
x+log[2,(2^x-31)]=5log[2,(2^x-31)]底数2真数2^x -31
x+log[2,(2^x-31)]=5
log[2,(2^x-31)]
底数2
真数2^x -31
x+log[2,(2^x-31)]=5log[2,(2^x-31)]底数2真数2^x -31
x + log[2,(2^x-31)] = 5
log[2,(2^x-31)] = 5 - x
2^x - 31 = 2^(5 - x)
2^x - 31 = 2^5/2^x
令 u = 2^x
u^2 - 31u - 32 = 0
(u - 32)(u - 1) = 0
u = 32 .x = 5
u = 1 .x = 0 .2^x - 31 < 0
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x+log[2,(2^x-31)]=5log[2,(2^x-31)]底数2真数2^x -31
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