数值：sin9π/4+cos2π/3+tan5π/4
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数值：sin9π/4+cos2π/3+tan5π/4数值：sin9π/4+cos2π/3+tan5π/4数值：sin9π/4+cos2π/3+tan5π/4sin9π/4=sin(9π/4-2π)=s
数值：sin9π/4+cos2π/3+tan5π/4
数值：sin9π/4+cos2π/3+tan5π/4
数值：sin9π/4+cos2π/3+tan5π/4
sin9π/4=sin(9π/4-2π)=sinπ/4=√2/2
tan5π/4=tan(5π/4-π)=tanπ/4=1
所以原式=√2/2-1/2+1=√2/2+1/2
数值：sin9π/4+cos2π/3+tan5π/4
数值：sin9π/4+cos2π/3+tan5π/4
sin9π/4+cos2π/3+tan5π/4的值.
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