(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/05 22:58:49
(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1=12a³+6a
(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1
(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1
(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1
=12a³+6a²-18a
(3a^n+1+6a^n+2-9a^n)/3a^n-1
(6a^n+2 +3a^n+1 -9a^n)/3a^n-1
计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1
分式 计算:a^(2n+1)-6a^(2n)+9a^(2n-1) / a^(n+1)-4a^n+3a^(n-1)
a^n+2+a^n+1-3a^n因式分解
计算(3a^n+1-6a^n+9a^n-1)/(1/3a^n-2)
计算:(6a^n+2-9a^n+1+3a^n-1)÷3a^n-1
(6a^n+2+3a^n+1-9a^n)÷1/2a^n-1
(3a^(n+1)+6a^(n+2)-9a^n)/3a^(n-1)是计算
(3a^n+1+6a^n+2-9a^n)/3a^n-1是计算题
如果n是正整数,[(8a^n+3)-(6a^n+2)-(5a^n+1)]/(-a)^n
数列a(n)=n (n+1)(n+2)(n+3),求S(n)
(4a^2n-6a^n+1+2a^n)/2a^n 因式分解
-a^n-(-5a^n-1)-2(a^n-1-3a^n)
设a,n∈N*证明a^2n-(-a)^n≥(a+1)×a^n
(3a^n-2)-6a^n+14a^n-1(因式分解) (m-n)^3+4(n-m)(n-2)和(n-1)最为指数
1.因式分解6(a-b)^2减8(a-b)^32.计算3a^(n+1)-6a^(n)+9a^(n-1)除以 三分之一a^(n-1
计算:(3a^(n+1)-6a^n+9a^(n-1)/(1/3a^(n-1)