解不等式:sin(2x-π/3)>1/2(x属于R)

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解不等式:sin(2x-π/3)>1/2(x属于R)解不等式:sin(2x-π/3)>1/2(x属于R)解不等式:sin(2x-π/3)>1/2(x属于R)sin(2x-π/3)>1/2所以2kπ+π

解不等式:sin(2x-π/3)>1/2(x属于R)
解不等式:sin(2x-π/3)>1/2(x属于R)

解不等式:sin(2x-π/3)>1/2(x属于R)
sin(2x-π/3)>1/2
所以2kπ+π/6