∫x/（x^2+5）dx

∫x/（x^2+5）dx ∫X√(2-5X)dx ∫（x-3x+2）dx 求不定积分∫x√（2-5x）dx ∫√（5-4x-x^2）dx x-9/[(根号)x]+3 dx ∫ x+1/[(根号)x] dx ∫ [（3-x^2）]^2 dx ∫（2-3x）³dx ∫1/（2x+5）∧11dx ∫(3x-2)/(x^2-2x+5)dx ∫[（x+1)/(x^(2)+2x+5]dx ∫x/(x^4+2(x^2)+5)dx ∫2x²+3x-5/x+3dx ∫x/(x^2+5x+6)dx ∫x/(x^2-4x-5)dx ∫ x/√(x^2+4x+5)dx ∫1/(x(√x+x^(2/5)))dx ∫x/((x^2)+4x+5)dx ∫x／（1+2x）（1+x）dx ∫（(x+2)/4x(x^2-1)）dx