若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的值为

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若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的值为若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的值为若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的

若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的值为
若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的值为

若实数x,y满足^2-2xy+y^2+x-y-6=0.则x-y的值为
答:
实数x和y满足:
x^2-2xy+y^2+x-y-6=0
(x-y)^2+(x-y)-6=0 把x-y看做整体进行十字相乘法分解
(x-y+3)(x-y-2)=0
所以:
x-y=-3或者x-y=2