f(x)=sin(2x+π/6)设g(x)=f(X)-cos2x,求函数g(X)在区间x∈[0,π/2]上的最大值和最小值

设f(x)=sin(2x+π/6)+3/2,g(x)=f(x+a).若g(x)为偶函数,求a的值. 已知函数f(x)=sin(2x+π/2),设g(x)=f(x)+f(π/4-x),求函数g(x)的单调递增区间 已知函数f(x)=cos(2x-π/3)+2sin^2 x （2）设函数g（x）=[f（x)]^2+f(x),求g(x)的值域已知函数f(x)=cos(2x-π/3)+2sin^2 x（2）设函数g（x）=[f（x)]^2+f(x),求g(x)的值域 设0 ≤ x≤π/2,函数f(x)=sin(cosx),g(x)=cos(sinx),比较f(x)和g(X)的大小 设f(x-1)=x2_2x+3,g(sin x)=cos2 x+sin x-1,设f(x),g(x)的表达式.设f(x-1)=x2-2x+3,g(sin x)=cos2 x+sin x-1,设f(x),g(x)的表达式 函数f(x)=sin(2x+π/6),g(x)=cos(x+φ),|φ| -π/2>f(x)+g(x)f(x)-g(x)sin{g(x)} 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π