log7(3)=a log7(4)=b 求log49(48)

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log7(3)=alog7(4)=b求log49(48)log7(3)=alog7(4)=b求log49(48)log7(3)=alog7(4)=b求log49(48)log49(48)=LOG(7^

log7(3)=a log7(4)=b 求log49(48)
log7(3)=a log7(4)=b 求log49(48)

log7(3)=a log7(4)=b 求log49(48)
log49(48)
=LOG(7^2,(√48)^2)=LOG(7,(16*3)^(1/2))=(1/2)(LOG(7,4^2)+LOG(7,3))
=(1/2)(2LOG(7,4)+LOG(7,3))=(1/2)(2B+A)=B+A/2