若Ix+y1I+Iy+3I=0则x-y=?

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若Ix+y1I+Iy+3I=0则x-y=?若Ix+y1I+Iy+3I=0则x-y=?若Ix+y1I+Iy+3I=0则x-y=?x+y+1=y+3=0y=-3x=2x-y=2-(-3)=2+3=5希望能

若Ix+y1I+Iy+3I=0则x-y=?
若Ix+y1I+Iy+3I=0则x-y=?

若Ix+y1I+Iy+3I=0则x-y=?
x+y+1=y+3=0
y=-3 x=2
x-y=2-(-3)=2+3=5

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若Ix+y+1I+Iy+3I=0 第一个+1?
那么x+y+1=0 y+3=0
则x=2 y= -3
x-y
=2-(-3)
=5