若Ix-1I+Iy+3I -x+y-1/2=
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若Ix-1I+Iy+3I-x+y-1/2=若Ix-1I+Iy+3I-x+y-1/2=若Ix-1I+Iy+3I-x+y-1/2=若/x-1/+/y+3/=0,则-x+y-1/2=?因为绝对值具有非负性,
若Ix-1I+Iy+3I -x+y-1/2=
若Ix-1I+Iy+3I -x+y-1/2=
若Ix-1I+Iy+3I -x+y-1/2=
若/x-1/+/y+3/=0,则-x+y-1/2=?
因为绝对值具有非负性,则,结果为0,只可能为0+0,
则,x-1=0,y+3=0,x=1,y=-3
-x+y-1/2=1-3-1/2=-5/2
若Ix-1I+Iy+3I -x+y-1/2=
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