A={(x,y)|2x-y=1},B={(x,y)|5x+y=6},求A∩B
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A={(x,y)|2x-y=1},B={(x,y)|5x+y=6},求A∩BA={(x,y)|2x-y=1},B={(x,y)|5x+y=6},求A∩BA={(x,y)|2x-y=1},B={(x,y
A={(x,y)|2x-y=1},B={(x,y)|5x+y=6},求A∩B
A={(x,y)|2x-y=1},B={(x,y)|5x+y=6},求A∩B
A={(x,y)|2x-y=1},B={(x,y)|5x+y=6},求A∩B
联立方程
2x-y=1,5x+y=6
∴x=1,y=1
∴A∩B={(1,1)}
A∩B就是方程2x-y=1,5x+y=6的交点.
解得x=1,y=1
即A交B={(1,1)}
AB的元素是直线上的点
所以交集就是直线交点
联立2x-y=1
5x+y=6
x=1,y=1
所以A∩B={(1,1)}
A∩B={(1,1)}
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